Plates/Shells - Modeling Examples 

The finite element method is an approaching method. This means that the results will never be exact and can be made better and better, within reason, by sub-dividing the element mesh. Accurate results are dependent on the modeling of the problem.

The following pages are studies of finite element mesh fineness and its relationship to accurate stress and deflection results. These studies are meant to be an aide to help you select appropriate mesh fineness for a structure you are trying to model.  These studies will also answer the "why" many people ask when told they must use a "mesh" of elements to model a structural item (such as a shear wall) instead of using one giant element. Obviously these studies only give an overview of some basic elements and the engineer must be the final judge as to whether a specific finite element model is a good reflection of the "real" structure.

Shear Wall Modeling

Theoretical Deflection of Shear Wall with Point Load

Shear Wall Properties

L = 240 in

Area = 1440 in2

B = 12 in

H = 120 in.

E = 4000 ksi

n = 0.30

G = 1538.5 ksi

 

P = 15,000 kip

I = BH3/12
= 12(120)
3 / 12
= 1,728,000 in
4

Δ = PL3/3EI +
1.2 PL / AG
= 11.95 in

K = P / Δ
= 15,000k /11.95in
= 1255 kips/in

Stiffness as a Function of Mesh Fineness

 

Element
Mesh

1x1

1x2

2x2

2x4

4x8

Deflection
(in.)

4.54

8.07

8.26

10.43

11.29

Error

62%

33%

31%

13%

6%

Stiffness
K (kips/in)

3304.0

1858.7

1816.0

1438.2

1328.6

 

Note on Methodology:

Shear Wall Design Forces

Floor Shear Moment Elements

4

9.99k

100.05k-ft

P49-P52

3

20k

300.08k-ft

P33-P36

2

30k

600k-ft

P17-P20

1

40k

999.98k-ft

P1-P4

Shown above are the analysis results of a 4-story shear wall.  This example is for a straight shear wall, however the method and results are valid for box, channel, or any other shear wall shapes.

The RISA-2D files that were used to obtain these results are included as “4X1WALL.R3D” and “4X4WALL.R3D”.  The 10 kip story loads were applied uniformly across each story.  This was done to more accurately model loads being applied to the wall from a rigid or semi-rigid floor.

The story shears at each level were calculated as the sum of the FX corner forces.  The story moments at each level are calculated from the FY corner forces as shown below:

Mi = (Fyouter joint * 15ft) + (Fyinner joint * 7.5ft)

Story Shears - Hand Calculation

The story shears were calculated as shown below from the corner forces.  See the screen shot close up of the FX corner forces on the next page.

Story Sum FX Corner Forcers at Story Level (k) Shear Moment

4

[0.462 + 0.786 + 1.77 + 1.98] * 2 = 9.996

9.9k

P49-P52

3

[1.2 + 1.65 + 3.45 + 3.7] * 2 = 20.000

20k

P33-P36

2

[1.9 + 2.5 + 5.14 + 5.46] * 2 = 30.000

30k

P17-P20

1

[11.76 – 0.32 + 6.09 + 2.47] * 2 = 40.000

40k

P1-P4

 

For the graphical display of the corner forces, there are 4 corner forces shown for each plate. This is similar to a beam element which has 2 member end forces.

To get the story shear at any line, just sum up all the FX corner forces along the line.

Level 4 Global FX Corner Forces

 

 

To get the story moment at any line, just sum the moments obtained by multiplying the Fy corner forces along a line, times the moment arm such as the distance of each Fy force to the center of the wall.

Level 4 Global FY Corner Forces

 

Story Shears - Summation Tool

A quicker way to calculate story forces is to use the Internal Force Summation tool to have the program automatically calculate the global forces that pass through a given elevation of the shear wall. To do this, just click on the icon that appears below the selection toolbar whenever you have a set of valid, non-envelope solution results. This tool will sum the forces for the displayed items at the desired elevation and will report them back to the user in terms of the Global X, Y and Z directions.

For additional advice on this topic, please see the RISA Tips & Tricks webpage at risa.com/post/support. Type in Search keywords: Story Shears.

Story Moments

The story moments are calculated as the FY Corner forces times their moment arms.  The forces are symmetrical so each force on one side is multiplied by twice the arm length.

Story Sum FY Corner Forces * Moment Arm (k) Story Moment Elements

4

[3.92 k * 15' + (2.48 k + 3.02 k) * 7.5'] = 100.05 k'

100.1 kip-ft

P49-P52

3

[12.33 k * 15' + (7.9 k + 7.45 k) * 7.5'] = 300.075 k'

300.1 kip-ft

P33-P36

2

[24.93 k * 15' + (16.5 k + 13.64 k) * 7.5'] = 600.00 k'

600 kip-ft

P17-P20

1

[45.81 k * 15' + (25.16 k + 16.55 k) * 7.5'] = 999.975 k'

999.9 kip-ft

P1-P4

Shear Wall Penetrations 

 

Horizontal Deflection at Top

0.028 in.

0.033 in.

Shear @ A-A

10.82 kips

10.53 kips

Shear @ B_B

24.2 kips

23.08 kips

Shear @ C_C

33.74 kips

33.05 kips

Shear @ D-D

45.26 kips

47.35 kips

Reactions at E

10.8 kips

10.53 kips

Reactions at F

24.2 kips

23.06 kips

 

This is an example of a typical concrete shear wall with penetrations for windows and doors of various sizes.   The files for the models are WALLPEN1.R3D (coarse mesh) and WALLPEN2.R3D (fine mesh).  No theoretical solution results are given to compare with, however the two finite element densities are compared to observe the rate of convergence to the “true” answer.  The shears at the various lines are computed by adding up the X corner forces for the element corners closest to the lines.  The horizontal deflection is for the top of the wall.  A very rigid link is added to the top of the wall to simulate the effect of a concrete horizontal diaphragm.  This has the effect of stiffening the walls and spreading the load uniformly across the top of the wall.  The load is applied as a uniform load of 3.0 kips/ft. across the top of the wall.  The total width of the wall is 38 ft, so the total applied load is 114 kips.  The total height of the wall is 18 ft.

The “coarse” mesh on the left is an example of the minimum finite element mesh that should be used to model this type of wall.  Notice that the course mesh gives good results for the wall shears and reactions.  The overall deflection of the coarse mesh is off by about 15% from the “fine” mesh.  The coarse mesh tends to give too much stiffness to the slender walls around the loading door opening on the left, this can be seen in the larger reactions at points E and F as well in the horizontal deflections.  The fine mesh on the right shows that the slender wall sections are more flexible than shown by the coarse mesh and thus the reactions and wall shears are reduced for the slender wall sections.

Plate Connectivity Problems 

Shown below is a common modeling problem with plate elements. Since plates only have connectivity at their corner nodes, the applied load at middle joint connects to the plates below the joint, but not to the one above it. Because of this lack of connectivity, you see the joint "pushing through" the plate edge above in the plotted deflected shape.

The proper way to hand this type of mesh is with one of the mesh transitions described in the following section.

For additional advice on this topic, please see the RISA Tips & Tricks webpage at risa.com/post/support. Type in Search keywords: Plate Connectivity.

Mesh Transition Examples

Coarse Mesh to Fine Mesh

Shown below are two methods for transitioning from an area with a fine mesh to an area with a larger / coarser mesh. 

             

      Three to One                                     Two to One

Rectangular Mesh to Radial Mesh

Shown below are two methods for transitioning from an area with a rectangular mesh into an area with a radial mesh. 

                 

Square to Round                                                            Round to Square

For additional advice on this topic, please see the RISA Tips & Tricks webpage at risa.com/post/support. Type in Search keywords: Plate Mesh.